Integrand size = 24, antiderivative size = 112 \[ \int \frac {1}{(b d+2 c d x) \left (a+b x+c x^2\right )^3} \, dx=-\frac {1}{2 \left (b^2-4 a c\right ) d \left (a+b x+c x^2\right )^2}+\frac {4 c}{\left (b^2-4 a c\right )^2 d \left (a+b x+c x^2\right )}-\frac {32 c^2 \log (b+2 c x)}{\left (b^2-4 a c\right )^3 d}+\frac {16 c^2 \log \left (a+b x+c x^2\right )}{\left (b^2-4 a c\right )^3 d} \]
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Time = 0.04 (sec) , antiderivative size = 112, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.167, Rules used = {701, 695, 31, 642} \[ \int \frac {1}{(b d+2 c d x) \left (a+b x+c x^2\right )^3} \, dx=\frac {16 c^2 \log \left (a+b x+c x^2\right )}{d \left (b^2-4 a c\right )^3}-\frac {32 c^2 \log (b+2 c x)}{d \left (b^2-4 a c\right )^3}+\frac {4 c}{d \left (b^2-4 a c\right )^2 \left (a+b x+c x^2\right )}-\frac {1}{2 d \left (b^2-4 a c\right ) \left (a+b x+c x^2\right )^2} \]
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Rule 31
Rule 642
Rule 695
Rule 701
Rubi steps \begin{align*} \text {integral}& = -\frac {1}{2 \left (b^2-4 a c\right ) d \left (a+b x+c x^2\right )^2}-\frac {(4 c) \int \frac {1}{(b d+2 c d x) \left (a+b x+c x^2\right )^2} \, dx}{b^2-4 a c} \\ & = -\frac {1}{2 \left (b^2-4 a c\right ) d \left (a+b x+c x^2\right )^2}+\frac {4 c}{\left (b^2-4 a c\right )^2 d \left (a+b x+c x^2\right )}+\frac {\left (16 c^2\right ) \int \frac {1}{(b d+2 c d x) \left (a+b x+c x^2\right )} \, dx}{\left (b^2-4 a c\right )^2} \\ & = -\frac {1}{2 \left (b^2-4 a c\right ) d \left (a+b x+c x^2\right )^2}+\frac {4 c}{\left (b^2-4 a c\right )^2 d \left (a+b x+c x^2\right )}+\frac {\left (16 c^2\right ) \int \frac {b d+2 c d x}{a+b x+c x^2} \, dx}{\left (b^2-4 a c\right )^3 d^2}-\frac {\left (64 c^3\right ) \int \frac {1}{b+2 c x} \, dx}{\left (b^2-4 a c\right )^3 d} \\ & = -\frac {1}{2 \left (b^2-4 a c\right ) d \left (a+b x+c x^2\right )^2}+\frac {4 c}{\left (b^2-4 a c\right )^2 d \left (a+b x+c x^2\right )}-\frac {32 c^2 \log (b+2 c x)}{\left (b^2-4 a c\right )^3 d}+\frac {16 c^2 \log \left (a+b x+c x^2\right )}{\left (b^2-4 a c\right )^3 d} \\ \end{align*}
Time = 0.09 (sec) , antiderivative size = 87, normalized size of antiderivative = 0.78 \[ \int \frac {1}{(b d+2 c d x) \left (a+b x+c x^2\right )^3} \, dx=-\frac {\frac {\left (b^2-4 a c\right ) \left (b^2-8 b c x-4 c \left (3 a+2 c x^2\right )\right )}{(a+x (b+c x))^2}+64 c^2 \log (b+2 c x)-32 c^2 \log (a+x (b+c x))}{2 \left (b^2-4 a c\right )^3 d} \]
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Time = 2.39 (sec) , antiderivative size = 128, normalized size of antiderivative = 1.14
method | result | size |
default | \(\frac {-\frac {\frac {-4 c^{2} \left (4 a c -b^{2}\right ) x^{2}-4 b c \left (4 a c -b^{2}\right ) x -24 a^{2} c^{2}+8 a \,b^{2} c -\frac {b^{4}}{2}}{\left (c \,x^{2}+b x +a \right )^{2}}+16 c^{2} \ln \left (c \,x^{2}+b x +a \right )}{\left (4 a c -b^{2}\right )^{3}}+\frac {32 c^{2} \ln \left (2 c x +b \right )}{\left (4 a c -b^{2}\right )^{3}}}{d}\) | \(128\) |
risch | \(\frac {\frac {4 c^{2} x^{2}}{16 a^{2} c^{2}-8 a \,b^{2} c +b^{4}}+\frac {4 b c x}{16 a^{2} c^{2}-8 a \,b^{2} c +b^{4}}+\frac {12 a c -b^{2}}{32 a^{2} c^{2}-16 a \,b^{2} c +2 b^{4}}}{d \left (c \,x^{2}+b x +a \right )^{2}}+\frac {32 c^{2} \ln \left (2 c x +b \right )}{d \left (64 c^{3} a^{3}-48 a^{2} b^{2} c^{2}+12 a \,b^{4} c -b^{6}\right )}-\frac {16 c^{2} \ln \left (c \,x^{2}+b x +a \right )}{d \left (64 c^{3} a^{3}-48 a^{2} b^{2} c^{2}+12 a \,b^{4} c -b^{6}\right )}\) | \(209\) |
norman | \(\frac {\frac {4 c^{2} x^{2}}{d \left (16 a^{2} c^{2}-8 a \,b^{2} c +b^{4}\right )}+\frac {12 c^{3} a -b^{2} c^{2}}{2 c^{2} \left (16 a^{2} c^{2}-8 a \,b^{2} c +b^{4}\right ) d}+\frac {4 c b x}{d \left (16 a^{2} c^{2}-8 a \,b^{2} c +b^{4}\right )}}{\left (c \,x^{2}+b x +a \right )^{2}}+\frac {32 c^{2} \ln \left (2 c x +b \right )}{d \left (64 c^{3} a^{3}-48 a^{2} b^{2} c^{2}+12 a \,b^{4} c -b^{6}\right )}-\frac {16 c^{2} \ln \left (c \,x^{2}+b x +a \right )}{d \left (64 c^{3} a^{3}-48 a^{2} b^{2} c^{2}+12 a \,b^{4} c -b^{6}\right )}\) | \(223\) |
parallelrisch | \(\frac {32 a b \,c^{4} x -8 b^{3} c^{3} x -16 b^{2} c^{3} a +128 \ln \left (\frac {b}{2}+c x \right ) x a b \,c^{4}-64 \ln \left (c \,x^{2}+b x +a \right ) x a b \,c^{4}+32 a \,c^{5} x^{2}+128 \ln \left (\frac {b}{2}+c x \right ) x^{3} b \,c^{5}-64 \ln \left (c \,x^{2}+b x +a \right ) x^{3} b \,c^{5}+128 \ln \left (\frac {b}{2}+c x \right ) x^{2} a \,c^{5}+64 \ln \left (\frac {b}{2}+c x \right ) x^{2} b^{2} c^{4}-64 \ln \left (c \,x^{2}+b x +a \right ) x^{2} a \,c^{5}-32 \ln \left (c \,x^{2}+b x +a \right ) x^{2} b^{2} c^{4}+64 \ln \left (\frac {b}{2}+c x \right ) x^{4} c^{6}+64 \ln \left (\frac {b}{2}+c x \right ) a^{2} c^{4}-32 \ln \left (c \,x^{2}+b x +a \right ) a^{2} c^{4}-32 \ln \left (c \,x^{2}+b x +a \right ) x^{4} c^{6}-8 b^{2} c^{4} x^{2}+48 a^{2} c^{4}+b^{4} c^{2}}{2 \left (64 c^{3} a^{3}-48 a^{2} b^{2} c^{2}+12 a \,b^{4} c -b^{6}\right ) \left (c \,x^{2}+b x +a \right )^{2} c^{2} d}\) | \(337\) |
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Leaf count of result is larger than twice the leaf count of optimal. 386 vs. \(2 (110) = 220\).
Time = 0.40 (sec) , antiderivative size = 386, normalized size of antiderivative = 3.45 \[ \int \frac {1}{(b d+2 c d x) \left (a+b x+c x^2\right )^3} \, dx=-\frac {b^{4} - 16 \, a b^{2} c + 48 \, a^{2} c^{2} - 8 \, {\left (b^{2} c^{2} - 4 \, a c^{3}\right )} x^{2} - 8 \, {\left (b^{3} c - 4 \, a b c^{2}\right )} x - 32 \, {\left (c^{4} x^{4} + 2 \, b c^{3} x^{3} + 2 \, a b c^{2} x + a^{2} c^{2} + {\left (b^{2} c^{2} + 2 \, a c^{3}\right )} x^{2}\right )} \log \left (c x^{2} + b x + a\right ) + 64 \, {\left (c^{4} x^{4} + 2 \, b c^{3} x^{3} + 2 \, a b c^{2} x + a^{2} c^{2} + {\left (b^{2} c^{2} + 2 \, a c^{3}\right )} x^{2}\right )} \log \left (2 \, c x + b\right )}{2 \, {\left ({\left (b^{6} c^{2} - 12 \, a b^{4} c^{3} + 48 \, a^{2} b^{2} c^{4} - 64 \, a^{3} c^{5}\right )} d x^{4} + 2 \, {\left (b^{7} c - 12 \, a b^{5} c^{2} + 48 \, a^{2} b^{3} c^{3} - 64 \, a^{3} b c^{4}\right )} d x^{3} + {\left (b^{8} - 10 \, a b^{6} c + 24 \, a^{2} b^{4} c^{2} + 32 \, a^{3} b^{2} c^{3} - 128 \, a^{4} c^{4}\right )} d x^{2} + 2 \, {\left (a b^{7} - 12 \, a^{2} b^{5} c + 48 \, a^{3} b^{3} c^{2} - 64 \, a^{4} b c^{3}\right )} d x + {\left (a^{2} b^{6} - 12 \, a^{3} b^{4} c + 48 \, a^{4} b^{2} c^{2} - 64 \, a^{5} c^{3}\right )} d\right )}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 246 vs. \(2 (104) = 208\).
Time = 1.82 (sec) , antiderivative size = 246, normalized size of antiderivative = 2.20 \[ \int \frac {1}{(b d+2 c d x) \left (a+b x+c x^2\right )^3} \, dx=\frac {32 c^{2} \log {\left (\frac {b}{2 c} + x \right )}}{d \left (4 a c - b^{2}\right )^{3}} - \frac {16 c^{2} \log {\left (\frac {a}{c} + \frac {b x}{c} + x^{2} \right )}}{d \left (4 a c - b^{2}\right )^{3}} + \frac {12 a c - b^{2} + 8 b c x + 8 c^{2} x^{2}}{32 a^{4} c^{2} d - 16 a^{3} b^{2} c d + 2 a^{2} b^{4} d + x^{4} \cdot \left (32 a^{2} c^{4} d - 16 a b^{2} c^{3} d + 2 b^{4} c^{2} d\right ) + x^{3} \cdot \left (64 a^{2} b c^{3} d - 32 a b^{3} c^{2} d + 4 b^{5} c d\right ) + x^{2} \cdot \left (64 a^{3} c^{3} d - 12 a b^{4} c d + 2 b^{6} d\right ) + x \left (64 a^{3} b c^{2} d - 32 a^{2} b^{3} c d + 4 a b^{5} d\right )} \]
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Leaf count of result is larger than twice the leaf count of optimal. 266 vs. \(2 (110) = 220\).
Time = 0.21 (sec) , antiderivative size = 266, normalized size of antiderivative = 2.38 \[ \int \frac {1}{(b d+2 c d x) \left (a+b x+c x^2\right )^3} \, dx=\frac {16 \, c^{2} \log \left (c x^{2} + b x + a\right )}{{\left (b^{6} - 12 \, a b^{4} c + 48 \, a^{2} b^{2} c^{2} - 64 \, a^{3} c^{3}\right )} d} - \frac {32 \, c^{2} \log \left (2 \, c x + b\right )}{{\left (b^{6} - 12 \, a b^{4} c + 48 \, a^{2} b^{2} c^{2} - 64 \, a^{3} c^{3}\right )} d} + \frac {8 \, c^{2} x^{2} + 8 \, b c x - b^{2} + 12 \, a c}{2 \, {\left ({\left (b^{4} c^{2} - 8 \, a b^{2} c^{3} + 16 \, a^{2} c^{4}\right )} d x^{4} + 2 \, {\left (b^{5} c - 8 \, a b^{3} c^{2} + 16 \, a^{2} b c^{3}\right )} d x^{3} + {\left (b^{6} - 6 \, a b^{4} c + 32 \, a^{3} c^{3}\right )} d x^{2} + 2 \, {\left (a b^{5} - 8 \, a^{2} b^{3} c + 16 \, a^{3} b c^{2}\right )} d x + {\left (a^{2} b^{4} - 8 \, a^{3} b^{2} c + 16 \, a^{4} c^{2}\right )} d\right )}} \]
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Time = 0.27 (sec) , antiderivative size = 188, normalized size of antiderivative = 1.68 \[ \int \frac {1}{(b d+2 c d x) \left (a+b x+c x^2\right )^3} \, dx=-\frac {32 \, c^{3} \log \left ({\left | 2 \, c x + b \right |}\right )}{b^{6} c d - 12 \, a b^{4} c^{2} d + 48 \, a^{2} b^{2} c^{3} d - 64 \, a^{3} c^{4} d} + \frac {16 \, c^{2} \log \left (c x^{2} + b x + a\right )}{b^{6} d - 12 \, a b^{4} c d + 48 \, a^{2} b^{2} c^{2} d - 64 \, a^{3} c^{3} d} - \frac {b^{4} - 16 \, a b^{2} c + 48 \, a^{2} c^{2} - 8 \, {\left (b^{2} c^{2} - 4 \, a c^{3}\right )} x^{2} - 8 \, {\left (b^{3} c - 4 \, a b c^{2}\right )} x}{2 \, {\left (c x^{2} + b x + a\right )}^{2} {\left (b^{2} - 4 \, a c\right )}^{3} d} \]
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Time = 9.89 (sec) , antiderivative size = 239, normalized size of antiderivative = 2.13 \[ \int \frac {1}{(b d+2 c d x) \left (a+b x+c x^2\right )^3} \, dx=\frac {\frac {12\,a\,c-b^2}{2\,\left (16\,a^2\,c^2-8\,a\,b^2\,c+b^4\right )}+\frac {4\,c^2\,x^2}{16\,a^2\,c^2-8\,a\,b^2\,c+b^4}+\frac {4\,b\,c\,x}{16\,a^2\,c^2-8\,a\,b^2\,c+b^4}}{a^2\,d+x^2\,\left (d\,b^2+2\,a\,c\,d\right )+c^2\,d\,x^4+2\,b\,c\,d\,x^3+2\,a\,b\,d\,x}-\frac {32\,c^2\,\ln \left (b+2\,c\,x\right )}{-64\,d\,a^3\,c^3+48\,d\,a^2\,b^2\,c^2-12\,d\,a\,b^4\,c+d\,b^6}+\frac {16\,c^2\,\ln \left (c\,x^2+b\,x+a\right )}{-64\,d\,a^3\,c^3+48\,d\,a^2\,b^2\,c^2-12\,d\,a\,b^4\,c+d\,b^6} \]
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